What are the solutions to the equation 25x^2-40x=-16 ?

The solutions to the equation 25x^2-40x=-16 are x= 4/5

Find the zeros of 25x^2-40x=-16

The zeros of 25x^2-40x=-16 are x= 4/5

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25 x^{2} - 40 x = - 16

x = \frac{4}{5}

Decimal Notation

x = 0.8

Solution steps

25 x^{2} - 40 x = - 16

Move

16

to the left side

25 x^{2} - 40 x + 16 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 40 ) \pm ( - 40 ) ^{2} - 4 \cdot 25 \cdot 16}{2 \cdot 25}

(- 40)^{2} - 4 \cdot 25 \cdot 16 = 0

x_{1, 2} = \frac{- ( - 40 ) \pm 0}{2 \cdot 25}

x = \frac{- ( - 40 )}{2 \cdot 25}

\frac{- ( - 40 )}{2 \cdot 25} = \frac{4}{5}

x = \frac{4}{5}

The solution to the quadratic equation is:

x = \frac{4}{5}

- 30 + 13 x - x^{2}

5.2 + 0.04 m > 0.06 m

\frac{0}{4}

2 w^{2} + 18 w + 29 = (w + 6)^{2}

121 x^{2} - 144

What are the solutions to the equation 25x^2-40x=-16 ?
The solutions to the equation 25x^2-40x=-16 are x= 4/5
Find the zeros of 25x^2-40x=-16
The zeros of 25x^2-40x=-16 are x= 4/5