Solution
Solution
+1
Solution steps
Move to the right side
For the solutions are
Solve
Solve
The solutions to the quadratic equation are:
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Frequently Asked Questions (FAQ)
What are the solutions to the equation (0-3)^2+(y-4)^2=36 ?
The solutions to the equation (0-3)^2+(y-4)^2=36 are y=3sqrt(3)+4,y=-3sqrt(3)+4Find the zeros of (0-3)^2+(y-4)^2=36
The zeros of (0-3)^2+(y-4)^2=36 are y=3sqrt(3)+4,y=-3sqrt(3)+4