What are the solutions to the equation 3n^2+8n+16=2n^2 ?

The solutions to the equation 3n^2+8n+16=2n^2 are n=-4

Find the zeros of 3n^2+8n+16=2n^2

The zeros of 3n^2+8n+16=2n^2 are n=-4

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3 n^{2} + 8 n + 16 = 2 n^{2}

n = - 4

Solution steps

3 n^{2} + 8 n + 16 = 2 n^{2}

Move

2 n^{2}

to the left side

n^{2} + 8 n + 16 = 0

Solve with the quadratic formula

n_{1, 2} = \frac{- 8 \pm 8 ^{2} - 4 \cdot 1 \cdot 16}{2 \cdot 1}

8^{2} - 4 \cdot 1 \cdot 16 = 0

n_{1, 2} = \frac{- 8 \pm 0}{2 \cdot 1}

n = \frac{- 8}{2 \cdot 1}

\frac{- 8}{2 \cdot 1} = - 4

n = - 4

The solution to the quadratic equation is:

n = - 4

2 \geq \frac{n}{4} - 2

4 x + 3 < 15

m^{2} + 2 m + 5 = 0

2 - 16

\frac{1}{7} s = \frac{5}{7}

What are the solutions to the equation 3n^2+8n+16=2n^2 ?
The solutions to the equation 3n^2+8n+16=2n^2 are n=-4
Find the zeros of 3n^2+8n+16=2n^2
The zeros of 3n^2+8n+16=2n^2 are n=-4