What is ((x^{-2}y^2)^0*3x^3y^0)/(y^3) ?

The solution to ((x^{-2}y^2)^0*3x^3y^0)/(y^3) is (3x^3)/(y^3)

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simplify ((x^{-2}y^2)^0*3x^3y^0)/(y^3)

simplify

\frac{( x ^{- 2} y ^{2} ) ^{0} \cdot 3 x ^{3} y ^{0}}{y ^{3}}

\frac{3 x ^{3}}{y ^{3}}

Solution steps

\frac{( x ^{- 2} y ^{2} ) ^{0} \cdot 3 x ^{3} y ^{0}}{y ^{3}}

Apply exponent rule:

a^{0} = 1,

assuming

a \neq = 0

(x^{- 2} y^{2})^{0} = 1

= \frac{1 \cdot 3 x ^{3} y ^{0}}{y ^{3}}

Apply exponent rule:

a^{0} = 1,

assuming

a \neq = 0

y^{0} = 1

= \frac{1 \cdot 3 x ^{3} \cdot 1}{y ^{3}}

Multiply the numbers:

1 \cdot 3 \cdot 1 = 3

= \frac{3 x ^{3}}{y ^{3}}

6 = x^{2} + x

x^{2} + 12 x = - 27

x^{4} y^{3} + 7 x^{2} y - 3 x^{3} y^{3}

(a + 16)^{2} = 16

s^{2} + 7 s t - 30 t^{2}

What is ((x^{-2}y^2)^0*3x^3y^0)/(y^3) ?
The solution to ((x^{-2}y^2)^0*3x^3y^0)/(y^3) is (3x^3)/(y^3)