What is 2log_{10}(x)+log_{10}(x+1)-1 ?

The solution to 2log_{10}(x)+log_{10}(x+1)-1 is log_{10}(x^2(x+1))-1

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simplify 2log_{10}(x)+log_{10}(x+1)-1

simplify

2 lo g_{10} (x) + lo g_{10} (x + 1) - 1

lo g_{10} (x^{2} (x + 1)) - 1

Solution steps

2 lo g_{10} (x) + lo g_{10} (x + 1) - 1

Apply log rule:

a lo g_{c} (b) = lo g_{c} (b^{a})

2 lo g_{10} (x) = lo g_{10} (x^{2})

= lo g_{10} (x^{2}) + lo g_{10} (x + 1) - 1

Apply log rule:

lo g_{c} (a) + lo g_{c} (b) = lo g_{c} (ab)

lo g_{10} (x^{2}) + lo g_{10} (x + 1) = lo g_{10} (x^{2} (x + 1))

= lo g_{10} (x^{2} (x + 1)) - 1

\frac{1}{3} (ln (y) - 2 ln (x + y))

ln (1.5 a e^{b t})

lo g_{10} (x (x - 1)^{2})

2 x ln (3 x) - 4 x - 4 ln (3 x) + 8

ln (\frac{( a + b ) ^{2}}{c})

What is 2log_{10}(x)+log_{10}(x+1)-1 ?
The solution to 2log_{10}(x)+log_{10}(x+1)-1 is log_{10}(x^2(x+1))-1