What is expand log_{10}(x(x-1)^2) ?

The solution to expand log_{10}(x(x-1)^2) is log_{10}(x)+2log_{10}(x-1)

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expand log_{10}(x(x-1)^2)

expand

lo g_{10} (x (x - 1)^{2})

lo g_{10} (x) + 2 lo g_{10} (x - 1)

Solution steps

lo g_{10} (x (x - 1)^{2})

Apply log rule:

lo g_{c} (ab) = lo g_{c} (a) + lo g_{c} (b)

lo g_{10} (x (x - 1)^{2}) = lo g_{10} (x) + lo g_{10} ((x - 1)^{2})

= lo g_{10} (x) + lo g_{10} ((x - 1)^{2})

Apply log rule:

lo g_{a} (x^{b}) = b \cdot lo g_{a} (x)

lo g_{10} ((x - 1)^{2}) = 2 lo g_{10} (x - 1)

= lo g_{10} (x) + 2 lo g_{10} (x - 1)

2 x ln (3 x) - 4 x - 4 ln (3 x) + 8

ln (\frac{( a + b ) ^{2}}{c})

ln (ab) + ln (\frac{a}{b})

y d x + x (ln (x) - ln (y) - 1) d y

ln (\frac{x y ^{2}}{z ^{4} e ^{x}})

What is expand log_{10}(x(x-1)^2) ?
The solution to expand log_{10}(x(x-1)^2) is log_{10}(x)+2log_{10}(x-1)