What is ydx+x(ln(x)-ln(y)-1)dy ?

The solution to ydx+x(ln(x)-ln(y)-1)dy is ydx+x(ln(x/y)-1)dy

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simplify ydx+x(ln(x)-ln(y)-1)dy

simplify

y d x + x (ln (x) - ln (y) - 1) d y

y d x + x (ln (\frac{x}{y}) - 1) d y

Solution steps

y d x + x (ln (x) - ln (y) - 1) d y

Apply log rule:

lo g_{c} (a) - lo g_{c} (b) = lo g_{c} (\frac{a}{b})

ln (x) - ln (y) = ln (\frac{x}{y})

= y d x + x (ln (\frac{x}{y}) - 1) d y

ln (\frac{x y ^{2}}{z ^{4} e ^{x}})

ln (2) + ln (6) - ln (4)

3 lo g_{2} (x + 8) - 5 lo g_{2} (x + 2)

- lo g_{10} (6.4 \cdot 1 0^{- 5})

2 lo g_{7} (x) + 3 lo g_{7} (y)

What is ydx+x(ln(x)-ln(y)-1)dy ?
The solution to ydx+x(ln(x)-ln(y)-1)dy is ydx+x(ln(x/y)-1)dy