What is ln((5x+1)/(7x^2-1)) ?

The solution to ln((5x+1)/(7x^2-1)) is ln(5x+1)-ln(7x^2-1)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

simplify ln((5x+1)/(7x^2-1))

simplify

ln (\frac{5 x + 1}{7 x ^{2} - 1})

ln (5 x + 1) - ln (7 x^{2} - 1)

Solution steps

ln (\frac{5 x + 1}{7 x ^{2} - 1})

Apply log rule:

lo g_{c} (\frac{a}{b}) = lo g_{c} (a) - lo g_{c} (b)

ln (\frac{5 x + 1}{7 x ^{2} - 1}) = ln (5 x + 1) - ln (7 x^{2} - 1)

= ln (5 x + 1) - ln (7 x^{2} - 1)

2 ln (- 0.884) + ln (4)

8 [ln (z) + ln (z + 5)] - 4 ln (z - 7)

4 lo g_{3} (x) + 3 lo g_{3} (y)

ln (r) + ln (t)

ln (\frac{3}{100})

What is ln((5x+1)/(7x^2-1)) ?
The solution to ln((5x+1)/(7x^2-1)) is ln(5x+1)-ln(7x^2-1)