What is 3/(x-1)< 2/(x+1) ?

The solution to 3/(x-1)< 2/(x+1) is x<-5\lor-1<x<1

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3/(x-1)< 2/(x+1)

\frac{3}{x - 1} < \frac{2}{x + 1}

x < - 5 or - 1 < x < 1

Interval Notation

(- \infty, - 5) \cup (- 1, 1)

Solution steps

\frac{3}{x - 1} < \frac{2}{x + 1}

Rewrite in standard form

\frac{x + 5}{( x - 1 ) ( x + 1 )} < 0

Identify the intervals

x < - 5 or - 1 < x < 1

x^{2} + 8 x - 46 = 0

f (x) = (\frac{5}{5 ^{x}})^{\frac{1}{( 1 - x )}}

\frac{( u ^{- 1} v ^{2} ) ^{2}}{( u ^{3} v ^{- 2} ) ^{3}}

0 \cdot x = 0

- π > - 3