What are the solutions to the equation 0=-2(x-3)^2+8 ?

The solutions to the equation 0=-2(x-3)^2+8 are x=5,x=1

Find the zeros of 0=-2(x-3)^2+8

The zeros of 0=-2(x-3)^2+8 are x=5,x=1

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

0 = - 2 (x - 3)^{2} + 8

x = 5, x = 1

Solution steps

0 = - 2 (x - 3)^{2} + 8

Switch sides

- 2 (x - 3)^{2} + 8 = 0

Move

8

to the right side

- 2 (x - 3)^{2} = - 8

Divide both sides by

- 2

(x - 3)^{2} = 4

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x - 3 = 4 : x = 5

Solve

x - 3 = - 4 : x = 1

The solutions to the quadratic equation are:

x = 5, x = 1

(52 t - 16 t^{2}) - 40

2 x^{2} - x - 45

345 \cdot 375

∣ x - 1 ∣ \cdot ∣ x + 2 ∣ = 3

0 = x^{2} - 4 x - 2

What are the solutions to the equation 0=-2(x-3)^2+8 ?
The solutions to the equation 0=-2(x-3)^2+8 are x=5,x=1
Find the zeros of 0=-2(x-3)^2+8
The zeros of 0=-2(x-3)^2+8 are x=5,x=1