What is 2log_{10}(w)+4log_{10}(z) ?

The solution to 2log_{10}(w)+4log_{10}(z) is log_{10}(w^2z^4)

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simplify 2log_{10}(w)+4log_{10}(z)

simplify

2 lo g_{10} (w) + 4 lo g_{10} (z)

lo g_{10} (w^{2} z^{4})

Solution steps

2 lo g_{10} (w) + 4 lo g_{10} (z)

Apply log rule:

a lo g_{c} (b) = lo g_{c} (b^{a})

2 lo g_{10} (w) = lo g_{10} (w^{2})

= lo g_{10} (w^{2}) + 4 lo g_{10} (z)

Apply log rule:

a lo g_{c} (b) = lo g_{c} (b^{a})

4 lo g_{10} (z) = lo g_{10} (z^{4})

= lo g_{10} (w^{2}) + lo g_{10} (z^{4})

Apply log rule:

lo g_{c} (a) + lo g_{c} (b) = lo g_{c} (ab)

lo g_{10} (w^{2}) + lo g_{10} (z^{4}) = lo g_{10} (w^{2} z^{4})

= lo g_{10} (w^{2} z^{4})

ln (- (y - 2)^{2} e^{3 (x + y)})

4 lo g_{10} (z) - lo g_{10} (x)

20 ln (\frac{87}{34})

ln (n θ^{2 n} x e^{- θ n x})

ln (a - b) - ln (a)

What is 2log_{10}(w)+4log_{10}(z) ?
The solution to 2log_{10}(w)+4log_{10}(z) is log_{10}(w^2z^4)