What is ln(y)+1/y-ln(yh) ?

The solution to ln(y)+1/y-ln(yh) is -ln(h)+1/y

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simplify ln(y)+1/y-ln(yh)

simplify

ln (y) + \frac{1}{y} - ln (y h)

- ln (h) + \frac{1}{y}

Solution steps

ln (y) + \frac{1}{y} - ln (y h)

Apply log rule:

lo g_{c} (a) - lo g_{c} (b) = lo g_{c} (\frac{a}{b})

ln (y) - ln (h y) = ln (\frac{y}{h y})

= ln (\frac{y}{h y}) + \frac{1}{y}

Cancel the common factor:

y

= ln (\frac{1}{h}) + \frac{1}{y}

Apply log rule:

lo g_{a} (\frac{1}{x}) = - lo g_{a} (x)

= - ln (h) + \frac{1}{y}

ln (\frac{e ^{x} y ^{3}}{x})

2 ln (v - 1) - ln (v + 1)

ln (- 0.05 q) 0.99

ln (8 x) + e x

- lo g_{10} (2.96 \cdot 1 0^{- 6})