What are the solutions to the equation (x-5)^2=28 ?

The solutions to the equation (x-5)^2=28 are x=2sqrt(7)+5,x=-2sqrt(7)+5

Find the zeros of (x-5)^2=28

The zeros of (x-5)^2=28 are x=2sqrt(7)+5,x=-2sqrt(7)+5

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(x - 5)^{2} = 28

x = 27 + 5, x = - 27 + 5

Decimal

x = 10.29150 \dots, x = - 0.29150 \dots

Solution steps

(x - 5)^{2} = 28

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x - 5 = 28 : x = 27 + 5

Solve

x - 5 = - 28 : x = - 27 + 5

The solutions to the quadratic equation are:

x = 27 + 5, x = - 27 + 5

x^{2} = ∣ x ∣

3 x^{3} + 26 x^{2} + 64 x + 32

4 n^{2} - 4 n + 1

82 + 25 - 52

8 (z + 3) = 32

What are the solutions to the equation (x-5)^2=28 ?
The solutions to the equation (x-5)^2=28 are x=2sqrt(7)+5,x=-2sqrt(7)+5
Find the zeros of (x-5)^2=28
The zeros of (x-5)^2=28 are x=2sqrt(7)+5,x=-2sqrt(7)+5