What is 2log_{10}(x-3)-log_{10}(x+1) ?

The solution to 2log_{10}(x-3)-log_{10}(x+1) is log_{10}(((x-3)^2)/(x+1))

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simplify 2log_{10}(x-3)-log_{10}(x+1)

simplify

2 lo g_{10} (x - 3) - lo g_{10} (x + 1)

lo g_{10} (\frac{( x - 3 ) ^{2}}{x + 1})

Solution steps

2 lo g_{10} (x - 3) - lo g_{10} (x + 1)

Apply log rule:

a lo g_{c} (b) = lo g_{c} (b^{a})

2 lo g_{10} (x - 3) = lo g_{10} ((x - 3)^{2})

= lo g_{10} ((x - 3)^{2}) - lo g_{10} (x + 1)

Apply log rule:

lo g_{c} (a) - lo g_{c} (b) = lo g_{c} (\frac{a}{b})

lo g_{10} ((x - 3)^{2}) - lo g_{10} (x + 1) = lo g_{10} (\frac{( x - 3 ) ^{2}}{x + 1})

= lo g_{10} (\frac{( x - 3 ) ^{2}}{x + 1})

ln (x 50 0^{- x})

5 lo g_{10} (x) - 4 lo g_{10} (x + 8)

ln (c^{1}) + 0.8 \cdot ln (c^{2})

14 - lo g_{10} (1.3 \cdot 1 0^{- 3})

ln (x ln (\frac{x}{e}))

What is 2log_{10}(x-3)-log_{10}(x+1) ?
The solution to 2log_{10}(x-3)-log_{10}(x+1) is log_{10}(((x-3)^2)/(x+1))