What is log_{10}((a+b)(a-b)^2) ?

The solution to log_{10}((a+b)(a-b)^2) is log_{10}(a+b)+2log_{10}(a-b)

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simplify log_{10}((a+b)(a-b)^2)

simplify

lo g_{10} ((a + b) (a - b)^{2})

lo g_{10} (a + b) + 2 lo g_{10} (a - b)

Solution steps

lo g_{10} ((a + b) (a - b)^{2})

Apply log rule:

lo g_{c} (ab) = lo g_{c} (a) + lo g_{c} (b)

lo g_{10} ((a + b) (a - b)^{2}) = lo g_{10} (a + b) + lo g_{10} ((a - b)^{2})

= lo g_{10} (a + b) + lo g_{10} ((a - b)^{2})

Apply log rule:

lo g_{a} (x^{b}) = b \cdot lo g_{a} (x)

lo g_{10} ((a - b)^{2}) = 2 lo g_{10} (a - b)

= lo g_{10} (a + b) + 2 lo g_{10} (a - b)

2 ln (x^{3} y \frac{1}{2})

lo g_{2} (49.92) - lo g_{2} (6.24)

ln (\frac{x}{e ^{7 x}})

\frac{19 ln ( \frac{8}{33} )}{9}

ln (\frac{54}{60})

What is log_{10}((a+b)(a-b)^2) ?
The solution to log_{10}((a+b)(a-b)^2) is log_{10}(a+b)+2log_{10}(a-b)