What is 4log_{b}(y)+6log_{b}(z) ?

The solution to 4log_{b}(y)+6log_{b}(z) is log_{b}(y^4z^6)

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simplify 4log_{b}(y)+6log_{b}(z)

simplify

4 lo g_{b} (y) + 6 lo g_{b} (z)

lo g_{b} (y^{4} z^{6})

Solution steps

4 lo g_{b} (y) + 6 lo g_{b} (z)

Apply log rule:

a lo g_{c} (b) = lo g_{c} (b^{a})

4 lo g_{b} (y) = lo g_{b} (y^{4})

= lo g_{b} (y^{4}) + 6 lo g_{b} (z)

Apply log rule:

a lo g_{c} (b) = lo g_{c} (b^{a})

6 lo g_{b} (z) = lo g_{b} (z^{6})

= lo g_{b} (y^{4}) + lo g_{b} (z^{6})

Apply log rule:

lo g_{c} (a) + lo g_{c} (b) = lo g_{c} (ab)

lo g_{b} (y^{4}) + lo g_{b} (z^{6}) = lo g_{b} (y^{4} z^{6})

= lo g_{b} (y^{4} z^{6})

\frac{ln ( 5 )}{ln ( 2 ) - ln ( 5 )}

lo g_{3} (\frac{1}{9 ( 8 )})

lo g_{10} (\frac{- 1}{a})

ln (\frac{4 + 3 x}{4 + x})

ln (3^{1 + x} \cdot 2^{x})

What is 4log_{b}(y)+6log_{b}(z) ?
The solution to 4log_{b}(y)+6log_{b}(z) is log_{b}(y^4z^6)