What is simplify-log_{10}(1x10^{7.4}) ?

The solution to simplify-log_{10}(1x10^{7.4}) is -log_{10}(x)-7.4

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

simplify-log_{10}(1x10^{7.4})

simplify

- lo g_{10} (1 x 1 0^{7.4})

- lo g_{10} (x) - 7.4

Solution steps

- lo g_{10} (1 \cdot x \cdot 1 0^{7.4})

Apply log rule:

lo g_{c} (ab) = lo g_{c} (a) + lo g_{c} (b)

lo g_{10} (1 \cdot x \cdot 1 0^{7.4}) = lo g_{10} (1) + lo g_{10} (x) + lo g_{10} (1 0^{7.4})

= - (lo g_{10} (x) + lo g_{10} (1) + lo g_{10} (1 0^{7.4}))

Apply log rule:

lo g_{a} (x^{b}) = b \cdot lo g_{a} (x)

lo g_{10} (1 0^{7.4}) = 7.4 lo g_{10} (10)

= - (lo g_{10} (1) + lo g_{10} (x) + 7.4 lo g_{10} (10))

lo g_{10} (1) = 0

7.4 lo g_{10} (10) = 7.4

= - (lo g_{10} (x) + 0 + 7.4)

Simplify

0 + lo g_{10} (x) + 7.4 : lo g_{10} (x) + 7.4

= - (lo g_{10} (x) + 7.4)

Distribute parentheses

= - (lo g_{10} (x)) - (7.4)

Apply minus-plus rules

+ (- a) = - a

= - lo g_{10} (x) - 7.4

3 ln (\frac{1}{2}) + ln (16)

ln (\frac{a ^{1}}{b ^{3} c ^{4}})

x^{4} - ln (x y) + 3^{2 x + y^{2}}

lo g_{4} (n) + 3 lo g_{4} (m)

- lo g_{10} (8.2 \cdot 1 0^{- 5})

What is simplify-log_{10}(1x10^{7.4}) ?
The solution to simplify-log_{10}(1x10^{7.4}) is -log_{10}(x)-7.4