What is log_{10}(-2(1+i)) ?

The solution to log_{10}(-2(1+i)) is log_{10}(2)+log_{10}(1+i)

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simplify log_{10}(-2(1+i))

simplify

lo g_{10} (- 2 (1 + i))

lo g_{10} (2) + lo g_{10} (1 + i)

Solution steps

lo g_{10} (- 2 (1 + i))

Apply log rule:

lo g_{c} (ab) = lo g_{c} (a) + lo g_{c} (b)

lo g_{10} (- 2 (1 + i)) = lo g_{10} (2) + lo g_{10} (1 + i)

= lo g_{10} (2) + lo g_{10} (1 + i)

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What is log_{10}(-2(1+i)) ?
The solution to log_{10}(-2(1+i)) is log_{10}(2)+log_{10}(1+i)