What is log_{4}((-x)/(x+1)) ?

The solution to log_{4}((-x)/(x+1)) is log_{4}(-x)-log_{4}(x+1)

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simplify log_{4}((-x)/(x+1))

simplify

lo g_{4} (\frac{- x}{x + 1})

lo g_{4} (- x) - lo g_{4} (x + 1)

Solution steps

lo g_{4} (\frac{- x}{x + 1})

Apply log rule:

lo g_{c} (\frac{a}{b}) = lo g_{c} (a) - lo g_{c} (b)

lo g_{4} (\frac{- x}{x + 1}) = lo g_{4} (- x) - lo g_{4} (x + 1)

= lo g_{4} (- x) - lo g_{4} (x + 1)

ln (1 - x^{2}) + ln (a)

ln (\frac{l ^{2}}{2 !} e^{- l})

ln (8) + 5 ln (x) + 3 ln (x^{2} + 8)

ln (6 \cdot 7)

ln (3 (x + 2)) - \frac{ln ( x + 2 )}{2}

What is log_{4}((-x)/(x+1)) ?
The solution to log_{4}((-x)/(x+1)) is log_{4}(-x)-log_{4}(x+1)