What are the solutions to the equation c^2+csqrt(3)=6 ?

The solutions to the equation c^2+csqrt(3)=6 are c=sqrt(3),c=-2sqrt(3)

Find the zeros of c^2+csqrt(3)=6

The zeros of c^2+csqrt(3)=6 are c=sqrt(3),c=-2sqrt(3)

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c^{2} + c 3 = 6

c = 3, c = - 23

Solution steps

c^{2} + c 3 = 6

Move

6

to the left side

c^{2} + c 3 - 6 = 0

Write in the standard form

a x^{2} + b x + c = 0

c^{2} + 3 c - 6 = 0

Solve with the quadratic formula

c_{1, 2} = \frac{- 3 \pm ( 3 ) ^{2} - 4 \cdot 1 \cdot ( - 6 )}{2 \cdot 1}

(3)^{2} - 4 \cdot 1 \cdot (- 6) = 33

c_{1, 2} = \frac{- 3 \pm 3 3}{2 \cdot 1}

Separate the solutions

c_{1} = \frac{- 3 + 3 3}{2 \cdot 1}, c_{2} = \frac{- 3 - 3 3}{2 \cdot 1}

c = \frac{- 3 + 3 3}{2 \cdot 1} : 3

c = \frac{- 3 - 3 3}{2 \cdot 1} : - 23

The solutions to the quadratic equation are:

c = 3, c = - 23

4 (- \frac{3}{2}) + \frac{1}{10} - (- \frac{3}{2}) (\frac{2}{5})

- 10 x^{5} - 5 x

3 (2 b - 6) + 2 = - 52

- 150 \cdot \frac{π}{180}

23 z + 5 z^{2} = 10

What are the solutions to the equation c^2+csqrt(3)=6 ?
The solutions to the equation c^2+csqrt(3)=6 are c=sqrt(3),c=-2sqrt(3)
Find the zeros of c^2+csqrt(3)=6
The zeros of c^2+csqrt(3)=6 are c=sqrt(3),c=-2sqrt(3)