What are the solutions to the equation 23z+5z^2=10 ?

The solutions to the equation 23z+5z^2=10 are z= 2/5 ,z=-5

Find the zeros of 23z+5z^2=10

The zeros of 23z+5z^2=10 are z= 2/5 ,z=-5

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23 z + 5 z^{2} = 10

z = \frac{2}{5}, z = - 5

Solution steps

23 z + 5 z^{2} = 10

Move

10

to the left side

23 z + 5 z^{2} - 10 = 0

Write in the standard form

a x^{2} + b x + c = 0

5 z^{2} + 23 z - 10 = 0

Solve with the quadratic formula

z_{1, 2} = \frac{- 23 \pm 2 3 ^{2} - 4 \cdot 5 ( - 10 )}{2 \cdot 5}

2 3^{2} - 4 \cdot 5 (- 10) = 27

z_{1, 2} = \frac{- 23 \pm 27}{2 \cdot 5}

Separate the solutions

z_{1} = \frac{- 23 + 27}{2 \cdot 5}, z_{2} = \frac{- 23 - 27}{2 \cdot 5}

z = \frac{- 23 + 27}{2 \cdot 5} : \frac{2}{5}

z = \frac{- 23 - 27}{2 \cdot 5} : - 5

The solutions to the quadratic equation are:

z = \frac{2}{5}, z = - 5

\frac{7}{30} + \frac{13}{30}

y = 4 y - 9

(x - 1)^{2} - 5 = 3

(4^{\frac{1}{2}})^{\frac{2}{3}}

- x \leq 9

What are the solutions to the equation 23z+5z^2=10 ?
The solutions to the equation 23z+5z^2=10 are z= 2/5 ,z=-5
Find the zeros of 23z+5z^2=10
The zeros of 23z+5z^2=10 are z= 2/5 ,z=-5