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Popular >

simplify 2*ln(1+y)-ln(1+x)

Solution

simplify

2 \cdot ln (1 + y) - ln (1 + x)

Solution

ln (\frac{( 1 + y ) ^{2}}{1 + x})

Solution steps

2 ln (1 + y) - ln (1 + x)

Apply log rule:

a lo g_{c} (b) = lo g_{c} (b^{a})

2 ln (y + 1) = ln ((y + 1)^{2})

= ln ((y + 1)^{2}) - ln (x + 1)

Apply log rule:

lo g_{c} (a) - lo g_{c} (b) = lo g_{c} (\frac{a}{b})

ln ((1 + y)^{2}) - ln (1 + x) = ln (\frac{( y + 1 ) ^{2}}{x + 1})

= ln (\frac{( 1 + y ) ^{2}}{1 + x})

Popular Examples

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lo g_{10} (a) - 2 lo g_{10} (b) + 3

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ln (16) + ln (7) - 3 ln (2)

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6.1 + lo g_{10} (\frac{B}{C})

Frequently Asked Questions (FAQ)

What is 2*ln(1+y)-ln(1+x) ?
The solution to 2*ln(1+y)-ln(1+x) is ln(((1+y)^2)/(1+x))