What are the solutions to the equation d^2+7=5 ?

The solutions to the equation d^2+7=5 are d=sqrt(2)i,d=-sqrt(2)i

Find the zeros of d^2+7=5

The zeros of d^2+7=5 are d=sqrt(2)i,d=-sqrt(2)i

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

d^{2} + 7 = 5

d = 2 i, d = - 2 i

Solution steps

d^{2} + 7 = 5

Move

7

to the right side

d^{2} = - 2

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

d = - 2, d = - - 2

- 2 = 2 i

- - 2 = - 2 i

d = 2 i, d = - 2 i

- d^{2} - 12 d + 4 = - 6 d^{2}

8 \cdot 20

20 \cdot 10

(32)^{\frac{3}{5}}

\frac{- 9 - 6 i}{- 3 - 2 i}

What are the solutions to the equation d^2+7=5 ?
The solutions to the equation d^2+7=5 are d=sqrt(2)i,d=-sqrt(2)i
Find the zeros of d^2+7=5
The zeros of d^2+7=5 are d=sqrt(2)i,d=-sqrt(2)i