What are the solutions to the equation x^2-3/4 x+1/8 =0 ?

The solutions to the equation x^2-3/4 x+1/8 =0 are x= 1/2 ,x= 1/4

Find the zeros of x^2-3/4 x+1/8 =0

The zeros of x^2-3/4 x+1/8 =0 are x= 1/2 ,x= 1/4

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x^{2} - \frac{3}{4} x + \frac{1}{8} = 0

x = \frac{1}{2}, x = \frac{1}{4}

Decimal Notation

x = 0.5, x = 0.25

Solution steps

x^{2} - \frac{3}{4} x + \frac{1}{8} = 0

Find Least Common Multiplier of

4, 8 : 8

Multiply by LCM=

8

x^{2} \cdot 8 - \frac{3}{4} x \cdot 8 + \frac{1}{8} \cdot 8 = 0 \cdot 8

Simplify

8 x^{2} - 6 x + 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 6 ) \pm ( - 6 ) ^{2} - 4 \cdot 8 \cdot 1}{2 \cdot 8}

(- 6)^{2} - 4 \cdot 8 \cdot 1 = 2

x_{1, 2} = \frac{- ( - 6 ) \pm 2}{2 \cdot 8}

Separate the solutions

x_{1} = \frac{- ( - 6 ) + 2}{2 \cdot 8}, x_{2} = \frac{- ( - 6 ) - 2}{2 \cdot 8}

x = \frac{- ( - 6 ) + 2}{2 \cdot 8} : \frac{1}{2}

x = \frac{- ( - 6 ) - 2}{2 \cdot 8} : \frac{1}{4}

The solutions to the quadratic equation are:

x = \frac{1}{2}, x = \frac{1}{4}

3 y - 2 y + 5 y = 0

4 (x - 5) = 32

x^{3} - x^{2} - 10 x - 8

7 ∣ 2 - 2 n ∣ + 10 \leq - 18

x^{2} + 6 x - 3 = 0

What are the solutions to the equation x^2-3/4 x+1/8 =0 ?
The solutions to the equation x^2-3/4 x+1/8 =0 are x= 1/2 ,x= 1/4
Find the zeros of x^2-3/4 x+1/8 =0
The zeros of x^2-3/4 x+1/8 =0 are x= 1/2 ,x= 1/4