What are the solutions to the equation x^2+6x-3=0 ?

The solutions to the equation x^2+6x-3=0 are x=-3+2sqrt(3),x=-3-2sqrt(3)

Find the zeros of x^2+6x-3=0

The zeros of x^2+6x-3=0 are x=-3+2sqrt(3),x=-3-2sqrt(3)

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x^{2} + 6 x - 3 = 0

x = - 3 + 23, x = - 3 - 23

Decimal Notation

x = 0.46410 \dots, x = - 6.46410 \dots

Solution steps

x^{2} + 6 x - 3 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 \cdot 1 \cdot ( - 3 )}{2 \cdot 1}

6^{2} - 4 \cdot 1 \cdot (- 3) = 43

x_{1, 2} = \frac{- 6 \pm 4 3}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 6 + 4 3}{2 \cdot 1}, x_{2} = \frac{- 6 - 4 3}{2 \cdot 1}

x = \frac{- 6 + 4 3}{2 \cdot 1} : - 3 + 23

x = \frac{- 6 - 4 3}{2 \cdot 1} : - 3 - 23

The solutions to the quadratic equation are:

x = - 3 + 23, x = - 3 - 23

2 (- 6 b + 11) - 42 = 10 (- b - 2) - 8

1 - \frac{5}{8}

- 2 x^{2} + x = 0

8.5 \cdot 1 0^{- 3} = \frac{x \cdot x}{( 2.3 \cdot 1 0 ^{- 2} ) ^{2}}

f a t^{48} x^{2} + 36 x

What are the solutions to the equation x^2+6x-3=0 ?
The solutions to the equation x^2+6x-3=0 are x=-3+2sqrt(3),x=-3-2sqrt(3)
Find the zeros of x^2+6x-3=0
The zeros of x^2+6x-3=0 are x=-3+2sqrt(3),x=-3-2sqrt(3)