What is the answer to 2(-6b+11)-42=10(-b-2)-8 ?

The answer to 2(-6b+11)-42=10(-b-2)-8 is b=4

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2(-6b+11)-42=10(-b-2)-8

2 (- 6 b + 11) - 42 = 10 (- b - 2) - 8

b = 4

Solution steps

2 (- 6 b + 11) - 42 = 10 (- b - 2) - 8

Expand

2 (- 6 b + 11) - 42 : - 12 b - 20

Expand

10 (- b - 2) - 8 : - 10 b - 28

- 12 b - 20 = - 10 b - 28

Move

20

to the right side

- 12 b = - 10 b - 8

Move

10 b

to the left side

- 2 b = - 8

Divide both sides by

- 2

b = 4

1 - \frac{5}{8}

- 2 x^{2} + x = 0

8.5 \cdot 1 0^{- 3} = \frac{x \cdot x}{( 2.3 \cdot 1 0 ^{- 2} ) ^{2}}

f a t^{48} x^{2} + 36 x

14 x + 23 = 14 x - 23

What is the answer to 2(-6b+11)-42=10(-b-2)-8 ?
The answer to 2(-6b+11)-42=10(-b-2)-8 is b=4
Solve for b: 2(-6b+11)-42=10(-b-2)-8
The solution is b=4