What is sqrt(16-16sin^2(θ)) ?

The solution to sqrt(16-16sin^2(θ)) is 4sqrt(cos^2(θ))

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simplify sqrt(16-16sin^2(θ))

simplify

16 - 16 sin^{2} (θ)

4 cos^{2} (θ)

Solution steps

16 - 16 sin^{2} (θ)

Factor

16 - 16 sin^{2} (θ) : 16 (1 - sin^{2} (θ))

= 16 (1 - sin^{2} (θ))

Apply radical rule:

assuming

a \geq 0, b \geq 0

= 16 - sin^{2} (θ) + 1

16 = 4

= 4 - sin^{2} (θ) + 1

Rewrite using trig identities

= 4 cos^{2} (θ)

3 tan (2 x - \frac{π}{3})

csc (36 0^{\circ} + x)

2 sin (3 x - \frac{π}{2})

4 - 4 sin^{2} (θ)

sin (π \cdot n)

What is sqrt(16-16sin^2(θ)) ?
The solution to sqrt(16-16sin^2(θ)) is 4sqrt(cos^2(θ))