What is factor 40(x+2)^2-18(x+2)-7 ?

The solution to factor 40(x+2)^2-18(x+2)-7 is (4x+9)(10x+13)

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factor 40(x+2)^2-18(x+2)-7

factor

40 (x + 2)^{2} - 18 (x + 2) - 7

(4 x + 9) (10 x + 13)

Solution steps

40 (x + 2)^{2} - 18 (x + 2) - 7

Expand

40 (x + 2)^{2} - 18 (x + 2) - 7 : 40 x^{2} + 142 x + 117

= 40 x^{2} + 142 x + 117

Factor

40 x^{2} + 142 x + 117 : (10 x + 13) (4 x + 9)

= (4 x + 9) (10 x + 13)

x^{2} + 1 2^{2} = 1 5^{2}

\frac{5}{3} - 4

\frac{6}{9} \cdot 15

\frac{2 !}{( 2 - 2 ) ! \cdot 2 !}

2 - 4 (\frac{2 x}{7} + \frac{1}{7}) = \frac{3}{2} - x

What is factor 40(x+2)^2-18(x+2)-7 ?
The solution to factor 40(x+2)^2-18(x+2)-7 is (4x+9)(10x+13)