What are the solutions to the equation 192x-12x^2=0 ?

The solutions to the equation 192x-12x^2=0 are x=0,x=16

Find the zeros of 192x-12x^2=0

The zeros of 192x-12x^2=0 are x=0,x=16

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192 x - 12 x^{2} = 0

x = 0, x = 16

Solution steps

192 x - 12 x^{2} = 0

Write in the standard form

a x^{2} + b x + c = 0

- 12 x^{2} + 192 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 192 \pm 19 2 ^{2} - 4 ( - 12 ) \cdot 0}{2 ( - 12 )}

19 2^{2} - 4 (- 12) \cdot 0 = 192

x_{1, 2} = \frac{- 192 \pm 192}{2 ( - 12 )}

Separate the solutions

x_{1} = \frac{- 192 + 192}{2 ( - 12 )}, x_{2} = \frac{- 192 - 192}{2 ( - 12 )}

x = \frac{- 192 + 192}{2 ( - 12 )} : 0

x = \frac{- 192 - 192}{2 ( - 12 )} : 16

The solutions to the quadratic equation are:

x = 0, x = 16

400 = 30 (25 - t^{2})

\frac{2.5}{2.5 - 3}

\frac{1}{2} - \frac{2}{3} x = \frac{1}{4}

9 n^{2} - 6 n

25 x^{2} - 40 x + 15

What are the solutions to the equation 192x-12x^2=0 ?
The solutions to the equation 192x-12x^2=0 are x=0,x=16
Find the zeros of 192x-12x^2=0
The zeros of 192x-12x^2=0 are x=0,x=16