What is 7sin((n+2)pi)-7sin(npi) ?

The solution to 7sin((n+2)pi)-7sin(npi) is 7sin(pi(n+2))

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simplify 7sin((n+2)pi)-7sin(npi)

simplify

7 sin ((n + 2) π) - 7 sin (nπ)

7 sin (π (n + 2))

Solution steps

7 sin ((n + 2) π) - 7 sin (nπ)

Use the basic trigonometric identity:

sin (nπ) = 0

= 7 sin (π (2 + n)) - 7 \cdot 0

Refine

= 7 sin (π (n + 2))

sin (\frac{π}{3} - x)

(2 csc (θ))^{2} - 4

f (x) = cos (9 0^{\circ} + arcsin (x))

sin (arccos (x + 3))

cos (- x) sin (- x) csc (- x)

What is 7sin((n+2)pi)-7sin(npi) ?
The solution to 7sin((n+2)pi)-7sin(npi) is 7sin(pi(n+2))