What are the solutions to the equation x(x-1)=42 ?

The solutions to the equation x(x-1)=42 are x=7,x=-6

Find the zeros of x(x-1)=42

The zeros of x(x-1)=42 are x=7,x=-6

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x (x - 1) = 42

x = 7, x = - 6

Solution steps

x (x - 1) = 42

Expand

x (x - 1) : x^{2} - x

x^{2} - x = 42

Move

42

to the left side

x^{2} - x - 42 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 1 ) \pm ( - 1 ) ^{2} - 4 \cdot 1 \cdot ( - 42 )}{2 \cdot 1}

(- 1)^{2} - 4 \cdot 1 \cdot (- 42) = 13

x_{1, 2} = \frac{- ( - 1 ) \pm 13}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 1 ) + 13}{2 \cdot 1}, x_{2} = \frac{- ( - 1 ) - 13}{2 \cdot 1}

x = \frac{- ( - 1 ) + 13}{2 \cdot 1} : 7

x = \frac{- ( - 1 ) - 13}{2 \cdot 1} : - 6

The solutions to the quadratic equation are:

x = 7, x = - 6

\frac{( \frac{2}{3} ) ^{5} ( \frac{4}{9} ) ^{- 5}}{( \frac{3}{4} ) ^{5}}

12 x^{2} + 20 x - 64 = 0

13 + 2 k = 3 k + 4 (k - 3)

4 x^{2} + 6 x + 2 = 0

3 b (b - 4) + 6 (b - 8)

What are the solutions to the equation x(x-1)=42 ?
The solutions to the equation x(x-1)=42 are x=7,x=-6
Find the zeros of x(x-1)=42
The zeros of x(x-1)=42 are x=7,x=-6