What is (sin(-2pi+θ))/(cos(3pi-θ)) ?

The solution to (sin(-2pi+θ))/(cos(3pi-θ)) is -tan(θ)

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simplify (sin(-2pi+θ))/(cos(3pi-θ))

simplify

\frac{sin ( - 2 π + θ )}{cos ( 3 π - θ )}

- tan (θ)

Solution steps

\frac{sin ( - 2 π + θ )}{cos ( 3 π - θ )}

Rewrite using trig identities

= \frac{sin ( θ )}{cos ( 3 π - θ )}

Rewrite using trig identities

= \frac{sin ( θ )}{- cos ( θ )}

Apply the fraction rule:

\frac{a}{- b} = - \frac{a}{b}

= - \frac{sin ( θ )}{cos ( θ )}

Rewrite using trig identities

= - tan (θ)

7 cos ((n + 2) π) - 7 cos (nπ)

cos (- 5 x)

sin (cot (- 1 (x)))

cos (nπ (- 1))

cos (kπ) - cos (- kπ)

What is (sin(-2pi+θ))/(cos(3pi-θ)) ?
The solution to (sin(-2pi+θ))/(cos(3pi-θ)) is -tan(θ)