What are the solutions to the equation 4^2+x^2=7^2 ?

The solutions to the equation 4^2+x^2=7^2 are x=sqrt(33),x=-sqrt(33)

Find the zeros of 4^2+x^2=7^2

The zeros of 4^2+x^2=7^2 are x=sqrt(33),x=-sqrt(33)

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4^{2} + x^{2} = 7^{2}

x = 33, x = - 33

Decimal Notation

x = 5.74456 \dots, x = - 5.74456 \dots

Solution steps

4^{2} + x^{2} = 7^{2}

Move

4^{2}

to the right side

x^{2} = 33

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 33, x = - 33

[3]

- 9 p^{2} + 100 = 0

∣ 3 x - 4 ∣ + 5 = 8

4 x^{2} - 2 x^{3} - 2 x

9 x^{2} - 6 x \geq - 1

What are the solutions to the equation 4^2+x^2=7^2 ?
The solutions to the equation 4^2+x^2=7^2 are x=sqrt(33),x=-sqrt(33)
Find the zeros of 4^2+x^2=7^2
The zeros of 4^2+x^2=7^2 are x=sqrt(33),x=-sqrt(33)