What is 8x+cos(x+pi)-x^2 ?

The solution to 8x+cos(x+pi)-x^2 is 8x-cos(x)-x^2

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simplify 8x+cos(x+pi)-x^2

simplify

8 x + cos (x + π) - x^{2}

8 x - cos (x) - x^{2}

Solution steps

8 x + cos (x + π) - x^{2}

Rewrite using trig identities

= 8 x - cos (x) - x^{2}

sin (arctan (\frac{t}{3}))

a r tan (\frac{- 41.42}{36.07})

1 + tan^{2} (c)

8 cos (x + 4 5^{\circ})

(- i) [sin ((4 i + 3) (i y + x) + 4 i + 3)]