What is (sec(x)sec(x)-1)tan(x)dx ?

The solution to (sec(x)sec(x)-1)tan(x)dx is tan^3(x)dx

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simplify (sec(x)sec(x)-1)tan(x)dx

simplify

(sec (x) sec (x) - 1) tan (x) d x

tan^{3} (x) d x

Solution steps

(sec (x) sec (x) - 1) tan (x) d x

sec (x) sec (x) = sec^{2} (x)

= tan (x) (sec^{2} (x) - 1) d x

Simplify

sec^{2} (x) - 1 : tan^{2} (x)

= tan^{2} (x) tan (x) d x

Apply exponent rule:

a^{b} \cdot a^{c} = a^{b + c}

tan^{2} (x) tan (x) = tan^{2 + 1} (x)

= tan^{2 + 1} (x) d x

Add the numbers:

2 + 1 = 3

= tan^{3} (x) d x

cos (18 0^{\circ} - (x + y))

a r cot (- \frac{3}{- 1})

5 cos (4 x + \frac{13 π}{8})

sin (arccos (\frac{x}{( x + 1 )}))

cot (arccos (\frac{x}{14}))

What is (sec(x)sec(x)-1)tan(x)dx ?
The solution to (sec(x)sec(x)-1)tan(x)dx is tan^3(x)dx