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Popular >

(x^2-16)*(x-6)>= 0

Solution

(x^{2} - 16) \cdot (x - 6) \geq 0

Solution

- 4 \leq x \leq 4 or x \geq 6

+1

Interval Notation

[- 4, 4] \cup [6, \infty)

Solution steps

(x^{2} - 16) (x - 6) \geq 0

Factor

(x^{2} - 16) (x - 6) : (x + 4) (x - 4) (x - 6)

(x + 4) (x - 4) (x - 6) \geq 0

Identify the intervals

- 4 \leq x \leq 4 or x \geq 6

Popular Examples

\frac{t}{4} + 8 \geq - 10

1/8 x^2+4x+28=0

\frac{1}{8} x^{2} + 4 x + 28 = 0

simplify pi/4*4 simplify

\frac{π}{4} \cdot 4

- x^{2} + 7 x - 10 \geq 0

((2t+5)(3t-1))/3+(t^2+5)/2 =(7t-5)/6+1

\frac{( 2 t + 5 ) ( 3 t - 1 )}{3} + \frac{t ^{2} + 5}{2} = \frac{7 t - 5}{6} + 1

Frequently Asked Questions (FAQ)

What is (x^2-16)*(x-6)>= 0 ?
The solution to (x^2-16)*(x-6)>= 0 is -4<= x<= 4\lor x>= 6