What is sqrt(b^2-b^2sin^2(x)) ?

The solution to sqrt(b^2-b^2sin^2(x)) is bsqrt(cos^2(x))

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simplify sqrt(b^2-b^2sin^2(x))

simplify

b^{2} - b^{2} sin^{2} (x)

b cos^{2} (x)

Solution steps

b^{2} - b^{2} sin^{2} (x)

Factor out common term

b^{2}

= b^{2} (1 - sin^{2} (x))

Apply radical rule:

assuming

a \geq 0, b \geq 0

= b^{2} - sin^{2} (x) + 1

Apply radical rule:

assuming

a \geq 0

b^{2} = b

= b - sin^{2} (x) + 1

Rewrite using trig identities

= cos^{2} (x) b

sin^{2 x} (- 1)

cos (- 3 t + \frac{π}{5})

sin (2 x + 5 π)

sin (2 nπ) - sin (nπ)

csc (arctan (\frac{x}{5}))

What is sqrt(b^2-b^2sin^2(x)) ?
The solution to sqrt(b^2-b^2sin^2(x)) is bsqrt(cos^2(x))