What are the solutions to the equation 4x^2-9x+2=0 ?

The solutions to the equation 4x^2-9x+2=0 are x=2,x= 1/4

Find the zeros of 4x^2-9x+2=0

The zeros of 4x^2-9x+2=0 are x=2,x= 1/4

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4 x^{2} - 9 x + 2 = 0

x = 2, x = \frac{1}{4}

Solution steps

4 x^{2} - 9 x + 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 9 ) \pm ( - 9 ) ^{2} - 4 \cdot 4 \cdot 2}{2 \cdot 4}

(- 9)^{2} - 4 \cdot 4 \cdot 2 = 7

x_{1, 2} = \frac{- ( - 9 ) \pm 7}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- ( - 9 ) + 7}{2 \cdot 4}, x_{2} = \frac{- ( - 9 ) - 7}{2 \cdot 4}

x = \frac{- ( - 9 ) + 7}{2 \cdot 4} : 2

x = \frac{- ( - 9 ) - 7}{2 \cdot 4} : \frac{1}{4}

The solutions to the quadratic equation are:

x = 2, x = \frac{1}{4}

\frac{4 x ^{- 2} y ^{4}}{8 x ^{3} ( y ^{- 2} ) ^{3}}

7 x^{2} + 9 x y + 2 y^{2}

∣ x + 1 ∣ = ∣ 3 - x ∣

x^{2} + x - 6

What are the solutions to the equation 4x^2-9x+2=0 ?
The solutions to the equation 4x^2-9x+2=0 are x=2,x= 1/4
Find the zeros of 4x^2-9x+2=0
The zeros of 4x^2-9x+2=0 are x=2,x= 1/4