What are the solutions to the equation x(2-x)=-2 ?

The solutions to the equation x(2-x)=-2 are x=1-sqrt(3),x=1+sqrt(3)

Find the zeros of x(2-x)=-2

The zeros of x(2-x)=-2 are x=1-sqrt(3),x=1+sqrt(3)

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x (2 - x) = - 2

x = 1 - 3, x = 1 + 3

Solution steps

x (2 - x) = - 2

Expand

x (2 - x) : 2 x - x^{2}

2 x - x^{2} = - 2

Move

2

to the left side

2 x - x^{2} + 2 = 0

Write in the standard form

a x^{2} + b x + c = 0

- x^{2} + 2 x + 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 ( - 1 ) \cdot 2}{2 ( - 1 )}

2^{2} - 4 (- 1) \cdot 2 = 23

x_{1, 2} = \frac{- 2 \pm 2 3}{2 ( - 1 )}

Separate the solutions

x_{1} = \frac{- 2 + 2 3}{2 ( - 1 )}, x_{2} = \frac{- 2 - 2 3}{2 ( - 1 )}

x = \frac{- 2 + 2 3}{2 ( - 1 )} : 1 - 3

x = \frac{- 2 - 2 3}{2 ( - 1 )} : 1 + 3

The solutions to the quadratic equation are:

x = 1 - 3, x = 1 + 3

x, x^{2} - k x + 1681 = 0

(2 x - 1)^{2} = (x + 1)^{2}

(x - 9)^{2} = - 36

5 - 2 x^{2} = 6 x

5 x^{2} - 7 = 5 + 2 x^{2}

What are the solutions to the equation x(2-x)=-2 ?
The solutions to the equation x(2-x)=-2 are x=1-sqrt(3),x=1+sqrt(3)
Find the zeros of x(2-x)=-2
The zeros of x(2-x)=-2 are x=1-sqrt(3),x=1+sqrt(3)