What are the solutions to the equation 5-2x^2=6x ?

The solutions to the equation 5-2x^2=6x are x=-(3+sqrt(19))/2 ,x=(sqrt(19)-3)/2

Find the zeros of 5-2x^2=6x

The zeros of 5-2x^2=6x are x=-(3+sqrt(19))/2 ,x=(sqrt(19)-3)/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

5 - 2 x^{2} = 6 x

x = - \frac{3 + 19}{2}, x = \frac{19 - 3}{2}

Solution steps

5 - 2 x^{2} = 6 x

Move

6 x

to the left side

5 - 2 x^{2} - 6 x = 0

Write in the standard form

a x^{2} + b x + c = 0

- 2 x^{2} - 6 x + 5 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 6 ) \pm ( - 6 ) ^{2} - 4 ( - 2 ) \cdot 5}{2 ( - 2 )}

(- 6)^{2} - 4 (- 2) \cdot 5 = 219

x_{1, 2} = \frac{- ( - 6 ) \pm 2 19}{2 ( - 2 )}

Separate the solutions

x_{1} = \frac{- ( - 6 ) + 2 19}{2 ( - 2 )}, x_{2} = \frac{- ( - 6 ) - 2 19}{2 ( - 2 )}

x = \frac{- ( - 6 ) + 2 19}{2 ( - 2 )} : - \frac{3 + 19}{2}

x = \frac{- ( - 6 ) - 2 19}{2 ( - 2 )} : \frac{19 - 3}{2}

The solutions to the quadratic equation are:

x = - \frac{3 + 19}{2}, x = \frac{19 - 3}{2}

5 x^{2} - 7 = 5 + 2 x^{2}

4 x^{2} - x + 16 + 3 x = 7 x - 12 - 5 x

2 x^{2} + 3 = 21

(2 x + 7) (x - 1) = 0

(x + 7) (x - 7) = - 3 x

What are the solutions to the equation 5-2x^2=6x ?
The solutions to the equation 5-2x^2=6x are x=-(3+sqrt(19))/2 ,x=(sqrt(19)-3)/2
Find the zeros of 5-2x^2=6x
The zeros of 5-2x^2=6x are x=-(3+sqrt(19))/2 ,x=(sqrt(19)-3)/2