What are the solutions to the equation 35x^2-26x-16=0 ?

The solutions to the equation 35x^2-26x-16=0 are x= 8/7 ,x=-2/5

Find the zeros of 35x^2-26x-16=0

The zeros of 35x^2-26x-16=0 are x= 8/7 ,x=-2/5

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35 x^{2} - 26 x - 16 = 0

x = \frac{8}{7}, x = - \frac{2}{5}

Solution steps

35 x^{2} - 26 x - 16 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 26 ) \pm ( - 26 ) ^{2} - 4 \cdot 35 ( - 16 )}{2 \cdot 35}

(- 26)^{2} - 4 \cdot 35 (- 16) = 54

x_{1, 2} = \frac{- ( - 26 ) \pm 54}{2 \cdot 35}

Separate the solutions

x_{1} = \frac{- ( - 26 ) + 54}{2 \cdot 35}, x_{2} = \frac{- ( - 26 ) - 54}{2 \cdot 35}

x = \frac{- ( - 26 ) + 54}{2 \cdot 35} : \frac{8}{7}

x = \frac{- ( - 26 ) - 54}{2 \cdot 35} : - \frac{2}{5}

The solutions to the quadratic equation are:

x = \frac{8}{7}, x = - \frac{2}{5}

x = - x^{2} + 30

16 x^{2} = 34 x - 15

576 x^{2} - 144 x + 25 = 0

50 x^{2} - 50 x + 13 = 0

72 = (8 x + 3) (8 x - 3)

What are the solutions to the equation 35x^2-26x-16=0 ?
The solutions to the equation 35x^2-26x-16=0 are x= 8/7 ,x=-2/5
Find the zeros of 35x^2-26x-16=0
The zeros of 35x^2-26x-16=0 are x= 8/7 ,x=-2/5