What are the solutions to the equation -x^2+3x-28=0 ?

The solutions to the equation -x^2+3x-28=0 are x= 3/2-i(sqrt(103))/2 ,x= 3/2+i(sqrt(103))/2

Find the zeros of -x^2+3x-28=0

The zeros of -x^2+3x-28=0 are x= 3/2-i(sqrt(103))/2 ,x= 3/2+i(sqrt(103))/2

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- x^{2} + 3 x - 28 = 0

x = \frac{3}{2} - i \frac{103}{2}, x = \frac{3}{2} + i \frac{103}{2}

Solution steps

- x^{2} + 3 x - 28 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 3 \pm 3 ^{2} - 4 ( - 1 ) ( - 28 )}{2 ( - 1 )}

Simplify

3^{2} - 4 (- 1) (- 28) : 103 i

x_{1, 2} = \frac{- 3 \pm 103 i}{2 ( - 1 )}

Separate the solutions

x_{1} = \frac{- 3 + 103 i}{2 ( - 1 )}, x_{2} = \frac{- 3 - 103 i}{2 ( - 1 )}

x = \frac{- 3 + 103 i}{2 ( - 1 )} : \frac{3}{2} - i \frac{103}{2}

x = \frac{- 3 - 103 i}{2 ( - 1 )} : \frac{3}{2} + i \frac{103}{2}

The solutions to the quadratic equation are:

x = \frac{3}{2} - i \frac{103}{2}, x = \frac{3}{2} + i \frac{103}{2}

x^{2} + 9 b^{2} = 0

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x^{2} - 8 x - 96 = 0

x (x - 3) = 12

(x + 13) (x - 7) = 0

What are the solutions to the equation -x^2+3x-28=0 ?
The solutions to the equation -x^2+3x-28=0 are x= 3/2-i(sqrt(103))/2 ,x= 3/2+i(sqrt(103))/2
Find the zeros of -x^2+3x-28=0
The zeros of -x^2+3x-28=0 are x= 3/2-i(sqrt(103))/2 ,x= 3/2+i(sqrt(103))/2