What are the solutions to the equation x^2-8x-96=0 ?

The solutions to the equation x^2-8x-96=0 are x=4(1+sqrt(7)),x=4(1-sqrt(7))

Find the zeros of x^2-8x-96=0

The zeros of x^2-8x-96=0 are x=4(1+sqrt(7)),x=4(1-sqrt(7))

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x^{2} - 8 x - 96 = 0

x = 4 (1 + 7), x = 4 (1 - 7)

Solution steps

x^{2} - 8 x - 96 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 8 ) \pm ( - 8 ) ^{2} - 4 \cdot 1 \cdot ( - 96 )}{2 \cdot 1}

(- 8)^{2} - 4 \cdot 1 \cdot (- 96) = 87

x_{1, 2} = \frac{- ( - 8 ) \pm 8 7}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 8 ) + 8 7}{2 \cdot 1}, x_{2} = \frac{- ( - 8 ) - 8 7}{2 \cdot 1}

x = \frac{- ( - 8 ) + 8 7}{2 \cdot 1} : 4 (1 + 7)

x = \frac{- ( - 8 ) - 8 7}{2 \cdot 1} : 4 (1 - 7)

The solutions to the quadratic equation are:

x = 4 (1 + 7), x = 4 (1 - 7)

x (x - 3) = 12

(x + 13) (x - 7) = 0

(3 x - 2)^{2} = 144

x, 3 x^{2} - x y^{2} = c

2 (x - 2)^{2} = 12

What are the solutions to the equation x^2-8x-96=0 ?
The solutions to the equation x^2-8x-96=0 are x=4(1+sqrt(7)),x=4(1-sqrt(7))
Find the zeros of x^2-8x-96=0
The zeros of x^2-8x-96=0 are x=4(1+sqrt(7)),x=4(1-sqrt(7))