What are the solutions to the equation x^2-7x+5/4 =0 ?

The solutions to the equation x^2-7x+5/4 =0 are x=(7+2sqrt(11))/2 ,x=(7-2sqrt(11))/2

Find the zeros of x^2-7x+5/4 =0

The zeros of x^2-7x+5/4 =0 are x=(7+2sqrt(11))/2 ,x=(7-2sqrt(11))/2

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x^{2} - 7 x + \frac{5}{4} = 0

x = \frac{7 + 2 11}{2}, x = \frac{7 - 2 11}{2}

Solution steps

x^{2} - 7 x + \frac{5}{4} = 0

Multiply both sides by

4

4 x^{2} - 28 x + 5 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 28 ) \pm ( - 28 ) ^{2} - 4 \cdot 4 \cdot 5}{2 \cdot 4}

(- 28)^{2} - 4 \cdot 4 \cdot 5 = 811

x_{1, 2} = \frac{- ( - 28 ) \pm 8 11}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- ( - 28 ) + 8 11}{2 \cdot 4}, x_{2} = \frac{- ( - 28 ) - 8 11}{2 \cdot 4}

x = \frac{- ( - 28 ) + 8 11}{2 \cdot 4} : \frac{7 + 2 11}{2}

x = \frac{- ( - 28 ) - 8 11}{2 \cdot 4} : \frac{7 - 2 11}{2}

The solutions to the quadratic equation are:

x = \frac{7 + 2 11}{2}, x = \frac{7 - 2 11}{2}

3 q^{2} - 105 q + 750 = 0

z^{2} - 7 z + 13 = 0

m x^{2} - 5 x + 2 = n x - 1

(2 x - 1) (x + 3) = 4

x^{2} - \frac{2}{3} x = \frac{3}{5}

What are the solutions to the equation x^2-7x+5/4 =0 ?
The solutions to the equation x^2-7x+5/4 =0 are x=(7+2sqrt(11))/2 ,x=(7-2sqrt(11))/2
Find the zeros of x^2-7x+5/4 =0
The zeros of x^2-7x+5/4 =0 are x=(7+2sqrt(11))/2 ,x=(7-2sqrt(11))/2