What are the solutions to the equation 3q^2-105q+750=0 ?

The solutions to the equation 3q^2-105q+750=0 are q=25,q=10

Find the zeros of 3q^2-105q+750=0

The zeros of 3q^2-105q+750=0 are q=25,q=10

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3 q^{2} - 105 q + 750 = 0

q = 25, q = 10

Solution steps

3 q^{2} - 105 q + 750 = 0

Solve with the quadratic formula

q_{1, 2} = \frac{- ( - 105 ) \pm ( - 105 ) ^{2} - 4 \cdot 3 \cdot 750}{2 \cdot 3}

(- 105)^{2} - 4 \cdot 3 \cdot 750 = 45

q_{1, 2} = \frac{- ( - 105 ) \pm 45}{2 \cdot 3}

Separate the solutions

q_{1} = \frac{- ( - 105 ) + 45}{2 \cdot 3}, q_{2} = \frac{- ( - 105 ) - 45}{2 \cdot 3}

q = \frac{- ( - 105 ) + 45}{2 \cdot 3} : 25

q = \frac{- ( - 105 ) - 45}{2 \cdot 3} : 10

The solutions to the quadratic equation are:

q = 25, q = 10

z^{2} - 7 z + 13 = 0

m x^{2} - 5 x + 2 = n x - 1

(2 x - 1) (x + 3) = 4

x^{2} - \frac{2}{3} x = \frac{3}{5}

3 x^{2} + 7 = 4

What are the solutions to the equation 3q^2-105q+750=0 ?
The solutions to the equation 3q^2-105q+750=0 are q=25,q=10
Find the zeros of 3q^2-105q+750=0
The zeros of 3q^2-105q+750=0 are q=25,q=10