What are the solutions to the equation 3x^2+7=4 ?

The solutions to the equation 3x^2+7=4 are x=i,x=-i

Find the zeros of 3x^2+7=4

The zeros of 3x^2+7=4 are x=i,x=-i

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

3 x^{2} + 7 = 4

x = i, x = - i

Solution steps

3 x^{2} + 7 = 4

Move

7

to the right side

3 x^{2} = - 3

Divide both sides by

3

x^{2} = - 1

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = - 1, x = - - 1

- 1 = i

- - 1 = - i

x = i, x = - i

x^{2} = a, a > 0

y, x = 3 lo g_{10} (y^{2})

x, M (x) = 4 x^{2} - 12 x + 8

25 x^{2} + 110 x + 121 = 0

3 (x - 3)^{2} = 27

What are the solutions to the equation 3x^2+7=4 ?
The solutions to the equation 3x^2+7=4 are x=i,x=-i
Find the zeros of 3x^2+7=4
The zeros of 3x^2+7=4 are x=i,x=-i