What are the solutions to the equation 25x^2+110x+121=0 ?

The solutions to the equation 25x^2+110x+121=0 are x=-11/5

Find the zeros of 25x^2+110x+121=0

The zeros of 25x^2+110x+121=0 are x=-11/5

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25 x^{2} + 110 x + 121 = 0

x = - \frac{11}{5}

Solution steps

25 x^{2} + 110 x + 121 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 110 \pm 11 0 ^{2} - 4 \cdot 25 \cdot 121}{2 \cdot 25}

11 0^{2} - 4 \cdot 25 \cdot 121 = 0

x_{1, 2} = \frac{- 110 \pm 0}{2 \cdot 25}

x = \frac{- 110}{2 \cdot 25}

\frac{- 110}{2 \cdot 25} = - \frac{11}{5}

x = - \frac{11}{5}

The solution to the quadratic equation is:

x = - \frac{11}{5}

3 (x - 3)^{2} = 27

(2 x - 1)^{2} - 5 (2 x - 1) - 6 = 0

(2 x + 1)^{2} + (2 x + 3)^{2} = 290

5 x^{2} - 3 x - 36 = 0

9 x^{2} + 36 x + 36 = 0

What are the solutions to the equation 25x^2+110x+121=0 ?
The solutions to the equation 25x^2+110x+121=0 are x=-11/5
Find the zeros of 25x^2+110x+121=0
The zeros of 25x^2+110x+121=0 are x=-11/5