What are the solutions to the equation 6(2x-3)^2-24=0 ?

The solutions to the equation 6(2x-3)^2-24=0 are x= 5/2 ,x= 1/2

Find the zeros of 6(2x-3)^2-24=0

The zeros of 6(2x-3)^2-24=0 are x= 5/2 ,x= 1/2

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6 (2 x - 3)^{2} - 24 = 0

x = \frac{5}{2}, x = \frac{1}{2}

Solution steps

6 (2 x - 3)^{2} - 24 = 0

Move

24

to the right side

6 (2 x - 3)^{2} = 24

Divide both sides by

6

(2 x - 3)^{2} = 4

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

2 x - 3 = 4 : x = \frac{5}{2}

Solve

2 x - 3 = - 4 : x = \frac{1}{2}

The solutions to the quadratic equation are:

x = \frac{5}{2}, x = \frac{1}{2}

4 (x - 5)^{2} = 20

2 x^{2} - (x + 2) (x - 3) = 12

x^{2} + 8 x = 6 x + 3

x^{2} - 2 x - 3 = x - 3

7 p^{2} - 7 p = 7 p

What are the solutions to the equation 6(2x-3)^2-24=0 ?
The solutions to the equation 6(2x-3)^2-24=0 are x= 5/2 ,x= 1/2
Find the zeros of 6(2x-3)^2-24=0
The zeros of 6(2x-3)^2-24=0 are x= 5/2 ,x= 1/2