What are the solutions to the equation 4(x-5)^2=20 ?

The solutions to the equation 4(x-5)^2=20 are x=sqrt(5)+5,x=-sqrt(5)+5

Find the zeros of 4(x-5)^2=20

The zeros of 4(x-5)^2=20 are x=sqrt(5)+5,x=-sqrt(5)+5

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4 (x - 5)^{2} = 20

x = 5 + 5, x = - 5 + 5

Solution steps

4 (x - 5)^{2} = 20

Divide both sides by

4

(x - 5)^{2} = 5

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x - 5 = 5 : x = 5 + 5

Solve

x - 5 = - 5 : x = - 5 + 5

The solutions to the quadratic equation are:

x = 5 + 5, x = - 5 + 5

2 x^{2} - (x + 2) (x - 3) = 12

x^{2} + 8 x = 6 x + 3

x^{2} - 2 x - 3 = x - 3

7 p^{2} - 7 p = 7 p

(x + 1)^{2} = 14

What are the solutions to the equation 4(x-5)^2=20 ?
The solutions to the equation 4(x-5)^2=20 are x=sqrt(5)+5,x=-sqrt(5)+5
Find the zeros of 4(x-5)^2=20
The zeros of 4(x-5)^2=20 are x=sqrt(5)+5,x=-sqrt(5)+5