What are the solutions to the equation (x+1)^2=14 ?

The solutions to the equation (x+1)^2=14 are x=sqrt(14)-1,x=-sqrt(14)-1

Find the zeros of (x+1)^2=14

The zeros of (x+1)^2=14 are x=sqrt(14)-1,x=-sqrt(14)-1

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(x + 1)^{2} = 14

x = 14 - 1, x = - 14 - 1

Decimal Notation

x = 2.74165 \dots, x = - 4.74165 \dots

Solution steps

(x + 1)^{2} = 14

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x + 1 = 14 : x = 14 - 1

Solve

x + 1 = - 14 : x = - 14 - 1

The solutions to the quadratic equation are:

x = 14 - 1, x = - 14 - 1

(x + 20) (x - 5) = 350

q^{2} - 22 q + 120 = 0

(x - 1) (x - 2) = 2

x, c y^{2} = x^{2} + y

(2 - 3 x)^{2} = 0

What are the solutions to the equation (x+1)^2=14 ?
The solutions to the equation (x+1)^2=14 are x=sqrt(14)-1,x=-sqrt(14)-1
Find the zeros of (x+1)^2=14
The zeros of (x+1)^2=14 are x=sqrt(14)-1,x=-sqrt(14)-1